Definition · applies to algebraic structures

Undergraduate (abstract algebra)

Consider a set $R$ with two binary operations, addition $+$ and multiplication $\cdot$. The set $R$ is a ring if

  1. $R$ with $+$ is a commutative group, whose identity element is written $0$,
  2. multiplication is associative and has an identity element, written $1$, and
  3. multiplication distributes over addition: $a (b + c) = a b + a c$ and $(a + b) c = a c + b c$ for all $a, b, c \in R$.

Examples

Examples

Non-examples

Things that may be mistaken for examples.

  • The nonzero real numbers, with multiplication High school
    The nonzero real numbers, with multiplication, do not form a ring, because a ring needs an addition too, and the nonzero real numbers are not closed under addition: $1 + (-1) = 0$.

Properties

  • Multiplication in a ring need not be commutative. A ring whose multiplication is commutative is called a commutative ring.
  • Elements of a ring need not have multiplicative inverses, so division need not be possible.
  • In every ring, $0 \cdot a = a \cdot 0 = 0$ and $(-1) \cdot a = -a$ for all $a$.

Notes

Some authors do not require a multiplicative identity $1$. Those authors call a ring with $1$ a unital ring, and some call a ring without $1$ a rng. Under that convention, the even integers form a ring; under the convention used here, they do not, because $1$ is not even.

Distinctions involving this term

  • Group vs. ring vs. field: Groups, rings, and fields are sets with operations that obey some of the rules of arithmetic. A group has one operation, which is associative, has an identity element, and can be undone. A ring has an addition and a multiplication; its addition forms a commutative group, but its elements need not have multiplicative inverses. A field is a commutative ring in which every nonzero element has a multiplicative inverse, so division by nonzero elements is possible.

All definitions · All distinctions · All examples