$x \mapsto \abs{x_1} + \abs{x_2}$ on $\reals^2$
Terms
| Term | This example | Why |
|---|---|---|
| norm | ✓ | $x \mapsto \abs{x_1} + \abs{x_2}$ is a norm. |
| inner product | ✗ | $x \mapsto \abs{x_1} + \abs{x_2}$ does not come from an inner product, because it fails the parallelogram law: with $x = (1, 0)$ and $y = (0, 1)$, $\norm{x + y}^2 + \norm{x - y}^2 = 8$, but $2 \norm{x}^2 + 2 \norm{y}^2 = 4$. |