$(x, y) \mapsto x y + 1$ on $\reals^2$

Example · Undergraduate

Terms

Term	This example	Why
bilinear form	✗	$(x, y) \mapsto x y + 1$ is not a bilinear form, because it is not linear in $x$: at $x = 0$, the output is $1$, not $0$.
inner product	✗	$(x, y) \mapsto x y + 1$ is not a inner_product because it is not a bilinear form.

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