Example · High school
Terms
| Term | This example | Why |
| diameter |
$1$
|
The diameter of $\mathbb{Q} \cap [0, 1]$ is $1$, because it contains $0$ and $1$.
|
| cardinality |
$\aleph_0$
|
The cardinality of $\mathbb{Q} \cap [0, 1]$ is $\aleph_0$, because its elements can be listed in order of their denominators.
|
| measure |
$0$
|
The Lebesgue measure of $\mathbb{Q} \cap [0, 1]$ is $0$, because it is countable: the $n$th rational number can be covered by an interval of length $\varepsilon / 2^n$, for a total length of at most $\varepsilon$.
|
| Hausdorff dimension |
$0$
|
The Hausdorff dimension of $\mathbb{Q} \cap [0, 1]$ is $0$, as for every countable set.
|
| infinite |
✓ |
|
| countably infinite |
✓ |
$\mathbb{Q} \cap [0, 1]$ is countably infinite, and so infinite, because its infinitely many fractions can be listed.
|
| bounded |
✓ |
|
| countable |
✓ |
$\mathbb{Q} \cap [0, 1]$ is countable because the fractions $p/q$ in $[0, 1]$ can be listed in order of their denominators $q$.
|
| uncountable |
✗ |
$\mathbb{Q} \cap [0, 1]$ is bounded, because all of its elements are between $0$ and $1$, and it is not uncountable.
|
| finite |
✗ |
$\mathbb{Q} \cap [0, 1]$ is not finite, because it contains $1/n$ for every $n \geq 1$.
|
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