$f \mapsto f^{\prime}$, on differentiable functions
Terms
| Term | This example | Why |
|---|---|---|
| function | ✓ | $f \mapsto f^{\prime}$ is a function, because it assigns one function to each differentiable function. |
| operator | ✓ | $f \mapsto f^{\prime}$ is an operator, because it takes a function and returns a function. |
| functional | ✗ | $f \mapsto f^{\prime}$, on differentiable functions, is not a functional, because its outputs are functions, not numbers. |