$x \mapsto \tan(x)$ on $(-\pi/2, \pi/2)$

Example · High school

Terms

Term	This example	Why
continuous	✓	$\tan$ is continuous on $(-\pi/2, \pi/2)$.
uniformly continuous	✗	$\tan$ is not uniformly continuous there, because its graph gets steeper without bound near the ends of the interval.

Distinctions using this example

• Continuous vs. uniformly continuous

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