$x \mapsto \sin(x)$ on $\reals$
Terms
| Term | This example | Why |
|---|---|---|
| continuous | ✓ | |
| uniformly continuous | ✓ | $\sin$ is uniformly continuous, and so continuous, because $\abs{\sin(x) - \sin(y)} \leq \abs{x - y}$, so the choice $\delta = \varepsilon$ works everywhere. |