$x \mapsto \sin(1/x)$ on $(0, \infty)$
Terms
| Term | This example | Why |
|---|---|---|
| continuous | ✓ | $x \mapsto \sin(1/x)$ is continuous on $(0, \infty)$. |
| uniformly continuous | ✗ | $x \mapsto \sin(1/x)$ is not uniformly continuous, because it oscillates between $-1$ and $1$ faster and faster as $x \to 0$. |