The interval $(0, 1]$
Terms
| Term | This example | Why |
|---|---|---|
| minimum | $\min (0, 1]$ does not exist | The infimum $0$ is not in the set. For every $x \in (0, 1]$, we can fine another value in the interval that is smaller. |
| maximum | $\max (0, 1] = 1$ | |
| infimum | $\inf (0, 1] = 0$ | |
| supremum | $\sup (0, 1] = 1$ | The maximum of $(0, 1]$ is $1$, which equals the supremum. |