Interior of a set
Elementary
The interior of a shape is the part on its inside, not including its edge.
Undergraduate (subsets of $\reals^n$)
A point $x$ is in the interior of $A$ if there exists an open ball around $x$ that is contained in $A$.
Examples
Worked examples
-
The closed unit disk $D = \setdef{(x, y) \suchthat x^2 + y^2 \leq 1}$
: $\operatorname{int} D = \setdef{(x, y) \suchthat x^2 + y^2 < 1}$
High school
The interior of the closed unit disk $D$ is the open disk.
-
$[0, 1]$
: $\operatorname{int} [0, 1] = (0, 1)$
High school
The interior of $[0, 1]$ is $(0, 1)$, because no interval around $0$ or $1$ stays inside $[0, 1]$.
-
$[0, 1)$, as a subset of $\reals$
: $\operatorname{int} [0, 1) = (0, 1)$
High school
The interior of $[0, 1)$ is $(0, 1)$, because every point of $(0, 1)$ has a small interval around it within $[0, 1)$.
-
$(0, 1)$
: $\operatorname{int} (0, 1) = (0, 1)$
High school
The interior of $(0, 1)$ is $(0, 1)$, because every point of $(0, 1)$ has a small interval around it inside $(0, 1)$; that is, $(0, 1)$ is open.
-
$\mathbb{Q}$, as a subset of $\reals$
: $\operatorname{int} \mathbb{Q} = \emptyset$
Undergraduate
Every interval contains rational and irrational numbers, so $\mathbb{Q}$ has an empty interior and an empty exterior.